Not quite. When you’re rotating, you are constantly accelerating in a tangent direction to the diameter. So the poster is right that we should be feeling a force shooting us away from the center of earth.
Except the force of gravity cancels out the centripetal force and then some.
So [force of gravity] - [centripetal force of Earth’s rotation] = 9.8m/s^2
The difference is about 0.5%. A mass weighing 100kg at the north pole would only weigh 99.5kg at the equator. Most of the difference is the centerfugal force of the earth’s rotation.
I’ve not checked the numbers, but apparently it’s detectable in Olympic sports. More height records get broken at equatorial latitudes that higher ones.
Only on the equator, the force is just tiny, it produces major weather systems through the coriolis effect but only on giant scales. This would be like saying people get dizzy if they stand near the pole.
The actual amount of centrifugal force is also tiny. Sure, it’s a relatively fast linear speed compared to something like a merry-go-round, but a merry-go-round’s angular velocity is much higher, and that’s the one you use when calculating the force trying to fling you off.
Also, centripetal force is the inward force observed by an external non-rotating reference frame which deflects motion into a curve. You’ve conflated it with centrifugal force, which is the outward “fictitious” force experienced in a rotating reference frame.
Have you seen the elementary school experiment where you spin an egg on a flat surface, then you stop the egg and let it go and the then the egg starts spinning again?
If the earth suddenly stopped spinning, the atmosphere would still be spinning at 1700km/h.
A cat 5 hurricane has wind speeds of 253km/h. So we’d be boned.
Not quite. When you’re rotating, you are constantly accelerating in a tangent direction to the diameter. So the poster is right that we should be feeling a force shooting us away from the center of earth.
Except the force of gravity cancels out the centripetal force and then some.
So [force of gravity] - [centripetal force of Earth’s rotation] = 9.8m/s^2
The difference is about 0.5%. A mass weighing 100kg at the north pole would only weigh 99.5kg at the equator. Most of the difference is the centerfugal force of the earth’s rotation.
I’ve not checked the numbers, but apparently it’s detectable in Olympic sports. More height records get broken at equatorial latitudes that higher ones.
That assumes a perfectly spherical earth. The earth is not perfectly spherical.
The fact that your units are units of acceleration proves the guys point, no?
It sounded like the guy meant the 1700km/h is a velocity, not an acceleration, which is why we don’t feel the force of acceleration.
I was pointing out that spinning is acceleration, just in this case we can’t feel it due to other forces.
Only on the equator, the force is just tiny, it produces major weather systems through the coriolis effect but only on giant scales. This would be like saying people get dizzy if they stand near the pole.
The actual amount of centrifugal force is also tiny. Sure, it’s a relatively fast linear speed compared to something like a merry-go-round, but a merry-go-round’s angular velocity is much higher, and that’s the one you use when calculating the force trying to fling you off.
Also, centripetal force is the inward force observed by an external non-rotating reference frame which deflects motion into a curve. You’ve conflated it with centrifugal force, which is the outward “fictitious” force experienced in a rotating reference frame.
What are those pre-math numbers though? How screwed would we be if rotation doubled or stopped (regardless of the virtual impossibility)?
Have you seen the elementary school experiment where you spin an egg on a flat surface, then you stop the egg and let it go and the then the egg starts spinning again?
If the earth suddenly stopped spinning, the atmosphere would still be spinning at 1700km/h.
A cat 5 hurricane has wind speeds of 253km/h. So we’d be boned.
Look up xkcd world stop spinning